Solution Sketch : Use ΔG°′ = –nFΔE°, where n = 2 electrons, F = 96.485 kJ V⁻¹ mol⁻¹, ΔE° = (+0.82 – (–0.32)) = 1.14 V → ΔG°′ ≈ –219 kJ mol⁻¹.
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